Use the image to answer the question.

A wheel is divided into 6 segments from the center toward circumference and labeled from the left as S, T, H, O, N, and E. The arrow of a needle points to O on the right and the circular end points to S on the left.

A spinner labeled with the letters of the word HONEST is to be spun once. Describe the probability of landing on an unshaded section in the sample space.

(1 point)
Responses

12
Start Fraction 1 over 2 End Fraction

13
Start Fraction 1 over 3 End Fraction

16
Start Fraction 1 over 6 End Fraction

3

1 answer

To determine the probability of landing on an unshaded section of the spinner labeled with the letters of the word HONEST, we first need to analyze the spinner:

  1. The word "HONEST" contains 6 letters: H, O, N, E, S, and T.
  2. The question indicates that the wheel is divided into 6 segments labeled S, T, H, O, N, and E. We need to identify which of these segments are shaded and which are unshaded. However, since you mentioned that the needle points to O and there is no indication of any shading in the segments, we will assume that all segments are equally likely to be landed upon.

Since all segments are considered in our probability calculation, and if we are given no further information regarding any segment being shaded or unshaded, we can state the following:

  • The total number of segments (or outcomes in our sample space) is 6.
  • Assuming that none of the segments are shaded, then the probability of landing on one of these segments (which would all be considered unshaded in absence of more info) is 6/6, which simplifies to 1 (or 100%).

However, if we interpret the question to mean the spinner must align with the segments for a probability calculation, and if we must select from a shaded/unshaded context where only certain segments are defined, then:

  • If all segments are equal, and assuming some segments are shaded affecting the calculations, let's consider the options that imply further division:

Given these interpretations and common understandings of probability with an assumption that all segments are unshaded:

  • The probability of landing on an unshaded section (if interpreting as specification) simplifies as \( \frac{1}{6} \) for the evaluation that applies across the segments.

Thus without specific visual data from the image and under provided simplifying assumptions, the probability response could be concluded:

Final Answer: \( \frac{1}{6} \) (1 out of 6 segments could reasonably be interpreted under common contexts).