Asked by Makenzie
A baseball just clears a 3.0m tall wall positioned 120m from home plate. If the ball left the bat 1.2 m above the ground at an angle of 45 degrees above the horizontal, how fast was it going when it left the bat.
Answers
Answered by
bobpursley
hfinal=hinitial+vsintheta*timeinair-4.9time^2
so,you have everything except timeinair.
Look at the horizontal equation:
120=vcosTheta*time
solve this for time in terms of v . THEn put it in the first equation, leaving a quadratic in terms of v.
solve for v, using the quadratic equation.
so,you have everything except timeinair.
Look at the horizontal equation:
120=vcosTheta*time
solve this for time in terms of v . THEn put it in the first equation, leaving a quadratic in terms of v.
solve for v, using the quadratic equation.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.