In the given exponential equation \( a_n = a_1 \cdot r^{n-1} \), the term \( a_1 \) represents the initial quantity (the starting amount) of the bacteria at \( n = 1 \).
Given that the bacteria quadruples (increases by a factor of 4) daily, we can denote the growth factor \( r \) as 4.
From the problem, we know that after the first day (\( n = 2 \)), the quantity of bacteria is 50. Thus:
\[ a_2 = a_1 \cdot r^{2-1} = a_1 \cdot r \]
Substituting the values we know:
\[ 50 = a_1 \cdot 4 \]
Now we can solve for \( a_1 \):
\[ a_1 = \frac{50}{4} = 12.5 \]
So, the value of \( a_1 \) is \( 12.5 \).