To find the length of segment AB in the described shape, it seems you have a rectangle with a length of 6 inches and a height of 4 inches, and there are two triangles (which I assume are right triangles) on either side of the rectangle.
Since you've mentioned only one triangle with a base of 10 inches, it's not immediately clear how AB relates to the rest of the shape. However, if we focus on the overall dimensions:
- The width of the rectangle is likely the 4 inches (commonly known as height in this case).
- The triangles could possibly have their bases aligned with the width of the rectangle.
Assuming AB is the total width:
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If the triangle's base of 10 inches is the length when placed at the bottom of the rectangle and the triangles are right triangles, we might be interested in how the rectilinear components contribute to the total width.
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If the rectangle (6 inches long) is between two triangles, and assuming each triangle extends outward:
- The total base length contributed by the two triangles would be the bottom triangle's base (10 inches) + any other extensions.
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If the triangles are effectively positioned such that one triangle's base corresponds to the total width played out when the rectangle is centered—e.g., AB represents the length from the leftmost point of the left triangle to the rightmost point on the right triangle, then length AB would be calculated thusly:
- Width of the Rectangle: 6 inches
- Base of Two Triangles (using only one triangle's base): 10 inches (divided between them)
Thus,
- The 6 inches of the rectangle does not impact the effective length of AB (the total length being focused on the angled parts of the triangles).
Final Calculation:
If AB was indeed to measure the total width impacted cumulatively by both triangles:
- Total Length = Width of rectangle (6 in) + Base of 2 triangles (10 in)
Total Length of AB = 6 in + 10 in = 16 in.
If this interpretation isn't what you meant, kindly provide more details about where AB is located or if the triangles have specific orientations.