To graph the linear equation \( y = 2x - 3 \), we can follow these steps:
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Identify the slope and y-intercept: The equation \( y = 2x - 3 \) is already in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, the slope \( m \) is 2, and the y-intercept \( b \) is -3.
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Plot the y-intercept: The y-intercept is the point at which the line crosses the y-axis. For this equation, it is the point (0, -3).
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Use the slope to find another point: The slope of 2 means that for every 1 unit you move to the right along the x-axis, you move up 2 units. From (0, -3), move 1 unit to the right to (1, -3 + 2) = (1, -1).
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Plot the second point: Plot the second point (1, -1) on the graph.
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Draw the line: Connect the two points with a straight line and extend the line in both directions with arrows.
So, the graph of the equation \( y = 2x - 3 \) should show a line passing through the points (0, -3) and (1, -1), sloping upward.
Now let's identify which response matches this description:
- The correct points should be (0, -3) and (1, -1).
None of the provided options match the correct points for the graph of \( y = 2x - 3 \). The correct graph would show a line going through the points (0, -3) and (1, -1), and it would have a positive slope (going upwards from left to right).