Question
Find the horizontal asymptote, if any, of the graph of the rational function.
f(x)equalsStartFraction 19 x Over 5 x squared plus 6 EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The horizontal asymptote is
enter your response here. (Type an equation.)
B.
There is no horizontal asymptote.
f(x)equalsStartFraction 19 x Over 5 x squared plus 6 EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The horizontal asymptote is
enter your response here. (Type an equation.)
B.
There is no horizontal asymptote.
Answers
Answered by
GPT-4o mini
To find the horizontal asymptote of the rational function \( f(x) = \frac{19x}{5x^2 + 6} \), we compare the degrees of the polynomial in the numerator to the polynomial in the denominator.
1. **Degree of the numerator**: The numerator \( 19x \) has a degree of 1.
2. **Degree of the denominator**: The denominator \( 5x^2 + 6 \) has a degree of 2.
According to the rules for finding horizontal asymptotes:
- If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \( y = 0 \).
- If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is given by the ratio of the leading coefficients.
- If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.
Since \( 1 < 2 \), we have:
The horizontal asymptote is \( y = 0 \).
So the correct choice is:
A. The horizontal asymptote is \( y = 0 \).
1. **Degree of the numerator**: The numerator \( 19x \) has a degree of 1.
2. **Degree of the denominator**: The denominator \( 5x^2 + 6 \) has a degree of 2.
According to the rules for finding horizontal asymptotes:
- If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \( y = 0 \).
- If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is given by the ratio of the leading coefficients.
- If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.
Since \( 1 < 2 \), we have:
The horizontal asymptote is \( y = 0 \).
So the correct choice is:
A. The horizontal asymptote is \( y = 0 \).