Question
Find the vertical asymptotes, if any, and the values of x corresponding to holes, if any, of the graph of the rational function.
h(x)equalsStartFraction x plus 3 Over x left parenthesis x plus 6 right parenthesis EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type an equation. Use a comma to separate answers as needed.)
A.
The vertical asymptote(s) is(are)
enter your response here. There are no holes.
B.
There are no vertical asymptotes but there is(are) hole(s) corresponding to
enter your response here.
C.
The vertical asymptote(s) is(are)
enter your response here and hole(s) corresponding to
enter your response here.
D.
There are no discontinuities.
h(x)equalsStartFraction x plus 3 Over x left parenthesis x plus 6 right parenthesis EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type an equation. Use a comma to separate answers as needed.)
A.
The vertical asymptote(s) is(are)
enter your response here. There are no holes.
B.
There are no vertical asymptotes but there is(are) hole(s) corresponding to
enter your response here.
C.
The vertical asymptote(s) is(are)
enter your response here and hole(s) corresponding to
enter your response here.
D.
There are no discontinuities.
Answers
Answered by
GPT-4o mini
To find the vertical asymptotes and holes of the function \( h(x) = \frac{x + 3}{x(x + 6)} \), we need to examine the denominator and see where it equals zero.
1. **Finding Vertical Asymptotes**:
- The vertical asymptotes occur where the denominator is equal to zero, but the numerator is not simultaneously equal to zero.
- The denominator \( x(x + 6) \) equals zero when:
\[
x = 0 \quad \text{or} \quad x + 6 = 0 \quad \Rightarrow \quad x = -6
\]
- Thus, the vertical asymptotes are at \( x = 0 \) and \( x = -6 \).
2. **Finding Holes**:
- A hole would occur if a factor in the denominator also appears in the numerator. In this function, the numerator \( x + 3 \) does not have common factors with the denominator \( x(x + 6) \).
- Therefore, there are no holes.
Summarizing the results:
- Vertical asymptotes: \( x = 0, -6 \)
- Holes: none
The final answer matches with choice **A**:
**A. The vertical asymptote(s) is(are)** \( x = 0, -6 \). **There are no holes.**
1. **Finding Vertical Asymptotes**:
- The vertical asymptotes occur where the denominator is equal to zero, but the numerator is not simultaneously equal to zero.
- The denominator \( x(x + 6) \) equals zero when:
\[
x = 0 \quad \text{or} \quad x + 6 = 0 \quad \Rightarrow \quad x = -6
\]
- Thus, the vertical asymptotes are at \( x = 0 \) and \( x = -6 \).
2. **Finding Holes**:
- A hole would occur if a factor in the denominator also appears in the numerator. In this function, the numerator \( x + 3 \) does not have common factors with the denominator \( x(x + 6) \).
- Therefore, there are no holes.
Summarizing the results:
- Vertical asymptotes: \( x = 0, -6 \)
- Holes: none
The final answer matches with choice **A**:
**A. The vertical asymptote(s) is(are)** \( x = 0, -6 \). **There are no holes.**
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