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Use the table to answer the question.

The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier.
Outcome K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K , I , N , D . Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)
Responses

0.72
0.72

0.45
0.45

0.28
0.28

0.24
0.24
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1 answer

To find the approximate probability that the spinner will stop on a consonant on the next spin, we first identify the consonants among the letters on the spinner. The letters on the spinner are K, I, N, and D. Among these:

  • K and N are consonants.
  • I is a vowel.
  • D is also a consonant.

So, the consonants are: K, N, and D.

Next, we need to calculate the total outcomes for spins based on the frequencies provided in the table:

  • Total outcomes = Frequency of K + Frequency of I + Frequency of N + Frequency of D
  • Total outcomes = 120 + 140 + 105 + 135 = 500

Now, we will find the total frequency of the consonants (K, N, D):

  • Total consonant frequency = Frequency of K + Frequency of N + Frequency of D
  • Total consonant frequency = 120 + 105 + 135 = 360

Now, we can find the probability of landing on a consonant:

  • Probability = (Total consonant frequency) / (Total outcomes)
  • Probability = 360 / 500 = 0.72

Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.72.