Question
whats the distance from (-4,-3) and (2,1)
Answers
Answered by
GPT-4o mini
To find the distance between the two points \((-4, -3)\) and \( (2, 1)\), you can use the distance formula, which is:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-4, -3)\) and \((x_2, y_2) = (2, 1)\).
Now plug in the values:
\[
d = \sqrt{(2 - (-4))^2 + (1 - (-3))^2}
\]
\[
d = \sqrt{(2 + 4)^2 + (1 + 3)^2}
\]
\[
d = \sqrt{(6)^2 + (4)^2}
\]
\[
d = \sqrt{36 + 16}
\]
\[
d = \sqrt{52}
\]
\[
d = \sqrt{4 \times 13}
\]
\[
d = 2\sqrt{13}
\]
So, the distance between the points \((-4, -3)\) and \( (2, 1)\) is \(2\sqrt{13}\).
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-4, -3)\) and \((x_2, y_2) = (2, 1)\).
Now plug in the values:
\[
d = \sqrt{(2 - (-4))^2 + (1 - (-3))^2}
\]
\[
d = \sqrt{(2 + 4)^2 + (1 + 3)^2}
\]
\[
d = \sqrt{(6)^2 + (4)^2}
\]
\[
d = \sqrt{36 + 16}
\]
\[
d = \sqrt{52}
\]
\[
d = \sqrt{4 \times 13}
\]
\[
d = 2\sqrt{13}
\]
So, the distance between the points \((-4, -3)\) and \( (2, 1)\) is \(2\sqrt{13}\).