Question

Challenge  A jewelry box has the shape of a rectangular prism. Find the volume of the jewelry box. If the height is increased by 3 in.​, by how much does the volume​ increase?
6 and one half in.
9 and one fourth in.
5 and one half in.
         ​ (The figure is not to​ scale.)
Question content area bottom
Part 1
The volume of the jewelry box is
  
enter your response here in.cubed.

Answers

GPT-4o mini
To find the volume of a rectangular prism (which is the shape of the jewelry box), you can use the formula:

\[
\text{Volume} = \text{length} \times \text{width} \times \text{height}
\]

Given:

- Height = \(6.5 \text{ in} = \frac{13}{2} \text{ in}\)
- Width = \(9.25 \text{ in} = \frac{37}{4} \text{ in}\)
- Length = \(5.5 \text{ in} = \frac{11}{2} \text{ in}\)

Now, let's calculate the volume:

1. Convert all dimensions into fractional form (if not already):
- Length = \( \frac{11}{2} \)
- Width = \( \frac{37}{4} \)
- Height = \( \frac{13}{2} \)

2. Plug these values into the volume formula:

\[
\text{Volume} = \frac{11}{2} \times \frac{37}{4} \times \frac{13}{2}
\]

3. Multiply the fractions together:

\[
\text{Volume} = \frac{11 \times 37 \times 13}{2 \times 4 \times 2}
\]

Calculating the numerator:

\[
11 \times 37 = 407
\]
\[
407 \times 13 = 5291
\]

Calculating the denominator:

\[
2 \times 4 \times 2 = 16
\]

Thus,

\[
\text{Volume} = \frac{5291}{16} \text{ in}^3
\]

4. The volume of the jewelry box is:

\[
\text{Volume} = 330.6875 \text{ in}^3 \quad \text{(approximately)}
\]

**Part 2: Increase in volume if height is increased by 3 inches**

If the height is increased by \(3 \text{ in}\), the new height will be:

\[
\text{New Height} = 6.5 + 3 = 9.5 \text{ in}
\]

Now calculate the new volume:

\[
\text{New Volume} = \text{length} \times \text{width} \times \text{new height}
\]
\[
\text{New Volume} = \frac{11}{2} \times \frac{37}{4} \times 9.5
\]

Convert \(9.5\) into an improper fraction for easier calculation:

\[
9.5 = \frac{19}{2}
\]

So:

\[
\text{New Volume} = \frac{11}{2} \times \frac{37}{4} \times \frac{19}{2}
\]

Now calculate:

1. Multiply:
\[
\text{New Volume} = \frac{11 \times 37 \times 19}{2 \times 4 \times 2}
\]

Calculating the new numerator:

\[
11 \times 37 = 407
\]
\[
407 \times 19 = 7723
\]

Calculating the denominator is the same as before:

\[
2 \times 4 \times 2 = 16
\]

Thus,

\[
\text{New Volume} = \frac{7723}{16} \text{ in}^3
\]

Now, we need to find the increase in volume:

\[
\text{Increase in Volume} = \text{New Volume} - \text{Original Volume}
\]

Substituting the values:

\[
\text{Increase in Volume} = \frac{7723}{16} - \frac{5291}{16} = \frac{7723 - 5291}{16} = \frac{2432}{16} = 152 \text{ in}^3
\]

**Final Results:**
- The volume of the jewelry box is approximately **330.69 in³**.
- The increase in volume, when the height is increased by 3 in., is **152 in³**.