Question

At a school carnival​ game, players toss beanbags onto a table with​ equal-sized squares of different colors. On the table there​ are:
8 green squares
5 orange squares
2 blue squares
Question content area bottom
Part 1
These statements describe the probabilities for different outcomes of a single beanbag toss that lands at a random location on the table. Select the number that best completes each statement.
The probability that the outcome is green is
A.0.133
0.133
B.0.333
0.333
C.0.533
0.533
D.0.8
0.8
The probability that the outcome is orange or green is
A.StartFraction 13 Over 15 EndFraction
StartFraction 13 Over 15 EndFraction
B.two fifteenths
two fifteenths
C.four fifths
four fifths
D.eight fifteenths
eight fifteenths

The probability that the outcome is not orange is
A.
33.3​%
B.80
80
C.66.7
66.7
D.
13.3​%

Answer 1

To solve the problem, we first need to determine the total number of squares on the table and then calculate the probabilities based on the number of squares of each color.

**Total Squares Calculation:**
- Green squares: 8
- Orange squares: 5
- Blue squares: 2

Total squares = 8 (green) + 5 (orange) + 2 (blue) = 15 squares

### Part 1: Probability that the outcome is green

The probability of landing on a green square is given by the number of green squares divided by the total number of squares:

\[
P(\text{Green}) = \frac{\text{Number of Green Squares}}{\text{Total Squares}} = \frac{8}{15} \approx 0.533
\]

So, **the probability that the outcome is green is**:
**C. 0.533**

### Part 2: Probability that the outcome is orange or green

The probability of landing on an orange or green square is given by the number of orange and green squares combined divided by the total number of squares:

\[
P(\text{Orange or Green}) = \frac{\text{Number of Orange Squares} + \text{Number of Green Squares}}{\text{Total Squares}} = \frac{5 + 8}{15} = \frac{13}{15}
\]

So, **the probability that the outcome is orange or green is**:
**A. StartFraction 13 Over 15 EndFraction**

### Part 3: Probability that the outcome is not orange

To find the probability that the outcome is not orange, we first calculate it as:

\[
P(\text{Not Orange}) = 1 - P(\text{Orange}) = 1 - \frac{\text{Number of Orange Squares}}{\text{Total Squares}} = 1 - \frac{5}{15} = \frac{10}{15} = \frac{2}{3} \approx 0.667
\]

Thus, as a percentage:

\[
P(\text{Not Orange}) \approx 66.7\%
\]

So, **the probability that the outcome is not orange is**:
**C. 66.7**

### Summary of Answers:
1. Probability outcome is green: **C. 0.533**
2. Probability outcome is orange or green: **A. StartFraction 13 Over 15 EndFraction**
3. Probability outcome is not orange: **C. 66.7**