To find the probability of selecting a blue marble and then selecting a yellow marble without replacing the blue marble, we can follow these steps:
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Calculate the probability of selecting a blue marble first. There are 3 blue marbles and a total of 16 marbles.
\[ P(\text{blue}) = \frac{3}{16} \]
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After selecting a blue marble, calculate the probability of selecting a yellow marble next. After removing one blue marble, there are now 15 marbles left in total (5 red, 2 blue, and 8 yellow).
\[ P(\text{yellow | blue}) = \frac{8}{15} \]
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Multiply the two probabilities to get the overall probability of selecting a blue marble first and then a yellow marble:
\[ P(\text{blue and then yellow}) = P(\text{blue}) \times P(\text{yellow | blue}) = \frac{3}{16} \times \frac{8}{15} \]
\[ = \frac{3 \times 8}{16 \times 15} = \frac{24}{240} \]
\[ = \frac{1}{10} \]
Therefore, the probability of selecting a blue marble and then a yellow marble is \( \frac{1}{10} \).
The correct response is: Start Fraction 1 over 10 End Fraction.