Question

The seventh-grade class at Prairie Junior High had a bake sale to raise money for a local charity.

They sold cookies for $1.25 and brownies for $2.15.

Part A

If the students sold 25 cookies and 19 brownies, how much money did they raise?

a $31.25

b $40.85

c $72.10

d $77.50

Part B

After two hours, the students decreased the price of the cookies by $0.10 and decreased the price of

the brownies by another amount. The students sold an additional 17 cookies and 12 brownies to earn

$42.95. By how many dollars did the students decrease the price of the brownies?

Enter your answer in the box.

Answers

GPT-4o mini
To solve the problem, we will tackle Part A first.

**Part A:**

1. Calculate the total money raised from selling cookies:
- The price of each cookie is $1.25.
- They sold 25 cookies.
- Total from cookies: \( 25 \times 1.25 = 31.25 \)

2. Calculate the total money raised from selling brownies:
- The price of each brownie is $2.15.
- They sold 19 brownies.
- Total from brownies: \( 19 \times 2.15 = 40.85 \)

3. Add the totals from cookies and brownies to find the total money raised:
- Total money raised: \( 31.25 + 40.85 = 72.10 \)

Thus, for Part A, the answer is **c $72.10**.

---

**Part B:**

1. Determine the new prices for the cookies and brownies after the price decrease.
- The new price for cookies after decreasing by $0.10:
- \( 1.25 - 0.10 = 1.15 \)

2. Now, let \( x \) be the decrease in the price of the brownies. The new price for brownies is:
- \( 2.15 - x \)

3. The students sold an additional 17 cookies and 12 brownies, raising a total of $42.95.
- Total from the additional cookies:
- \( 17 \times 1.15 = 19.55 \)
- Total from the additional brownies:
- \( 12 \times (2.15 - x) = 25.80 - 12x \)

4. Set up the equation for the total earnings from the additional sales:
- Combine both contributions:
\[
19.55 + (25.80 - 12x) = 42.95
\]

5. Simplify the equation:
\[
19.55 + 25.80 - 12x = 42.95
\]
\[
45.35 - 12x = 42.95
\]

6. Now, isolate \( x \):
\[
45.35 - 42.95 = 12x
\]
\[
2.40 = 12x
\]
\[
x = \frac{2.40}{12} = 0.20
\]

Thus, the students decreased the price of the brownies by **$0.20**.