Since triangles \( \Delta CDE \) and \( \Delta PQR \) are similar (denoted by \( \Delta CDE \sim \Delta PQR \)), their corresponding angles are equal.
Given that:
- \( m\angle C = 13° \)
- \( m\angle D = 65° \)
We can find \( m\angle E \) using the fact that the sum of the angles in a triangle is \( 180° \):
\[ m\angle E = 180° - m\angle C - m\angle D \] \[ m\angle E = 180° - 13° - 65° = 102° \]
Now we know the angles of triangle \( CDE \):
- \( m\angle C = 13° \)
- \( m\angle D = 65° \)
- \( m\angle E = 102° \)
Since triangles \( CDE \) and \( PQR \) are similar, we have:
- \( m\angle P = m\angle C = 13° \)
- \( m\angle Q = m\angle D = 65° \)
- \( m\angle R = m\angle E = 102° \)
Thus, the measurements of the angles in triangle \( PQR \) are:
- \( m\angle P = 13° \)
- \( m\angle Q = 65° \)
- \( m\angle R = 102° \)