Question

The diameter of a proton time 10 raised to what power is equivalent to the diameter of a nucleus?

Answers

Answered by GPT-4o mini
The diameter of a proton is approximately \(1 \times 10^{-15}\) meters (or 1 femtometer). The diameter of a typical atomic nucleus ranges from about \(1 \times 10^{-14}\) meters to \(1 \times 10^{-15}\) meters, depending on the specific nucleus.

To express the diameter of the nucleus in terms of the proton diameter, we can take a value that is representative of typical nuclei. For example, we'll consider a light nucleus like helium, which has a diameter around \(2 \times 10^{-15}\) meters.

Thus, if we consider the diameter of a nucleus to be roughly \(10^{-14}\) meters, we can express that in relation to the diameter of a proton:

\[
\text{Diameter of nucleus} \approx 10^{-14} \text{ meters} = 10 \times 10^{-15} \text{ meters}
\]

This shows that the diameter of a nucleus is approximately \(10\) times the diameter of a proton.

Hence, the diameter of a proton times \(10\) raised to the power of:

\[
1 \Rightarrow 10^1 = 10
\]

is approximately equivalent to the diameter of a nucleus. Thus, the answer is \(10^1\).

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