The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges, C

Question

, $500 for the ballroom rental fee and $75 per student, s
, for the meal. The Greenhill Country Club charges, C
, $1,000 for the ballroom rental fee and $65 per student, s
, for the meal. Create a pair of linear equations that represent this real-world problem.(1 point)
Responses

Regal Hotel: C=75s+1,000
; Greenhill Country Club: C=65s+500
Regal Hotel: upper C equals 75 s plus 1,000 ; Greenhill Country Club: upper C equals 65 s plus 500

Regal Hotel: C=500s+75
; Greenhill Country Club: C=1,000s+65
Regal Hotel: upper C equals 500 s plus 75 ; Greenhill Country Club: upper C equals 1,000 s plus 65

Regal Hotel: C=75s+500
; Greenhill Country Club: C=65s+1,000
Regal Hotel: upper C equals 75 s plus 500 ; Greenhill Country Club: upper C equals 65 s plus 1,000

Regal Hotel: C=1,000s+75
; Greenhill Country Club: C=500s+65

Answer 1

To create the pair of linear equations that represent the costs of holding prom at the two different locations, we need to consider both the rental fees and the cost per student meal for each venue.

1. Regal Hotel:

   • Rental fee: $500
   • Cost per student: $75
   • The equation is: \( C = 75s + 500 \)

2. Greenhill Country Club:

   • Rental fee: $1,000
   • Cost per student: $65
   • The equation is: \( C = 65s + 1000 \)

Thus, the correct pair of equations representing the costs for the two venues is:

• Regal Hotel: \( C = 75s + 500 \)
• Greenhill Country Club: \( C = 65s + 1000 \)

So the correct response is:

Regal Hotel: \( C = 75s + 500 \); Greenhill Country Club: \( C = 65s + 1000 \).