Did you mean x ---> 0 ?
Do you know L'Hopital's Rule?
Use it twice
lim (cosx - 1)/(2x^2
= lim -sinx/(4x)
= lim -cosx/4 = -1/4 as x ---> 0
What analytic method steps are required to find the limit of cos x-1/2x^2 ? Limit greater than 0. Estimating -0.25 but stalled ....
1 answer