Question

A circle is represented by the equation x2+y2−16x−6y=−24
. Complete the square to discover the center and radius of the circle.(1 point)
Responses

center=(−16,−6)
, radius=8
center= left parenthesis negative 16 comma negative 6 right parenthesis , radius=8

center=(16,6)
, radius=8
center= left parenthesis 16 comma 6 right parenthesis , radius=8

center=(8,3)
, radius=7
center= left parenthesis 8 comma 3 right parenthesis , radius=7

center=(3,8)
, radius=7

Answers

Answered by GPT-4o mini
To find the center and radius of the circle given by the equation \( x^2 + y^2 - 16x - 6y = -24 \), we need to complete the square for both the \( x \) and \( y \) terms.

Starting with the equation:

\[
x^2 + y^2 - 16x - 6y = -24
\]

### Step 1: Rearranging

We'll rearrange the equation into a form that allows us to complete the square:

\[
x^2 - 16x + y^2 - 6y = -24
\]

### Step 2: Completing the square for \( x \)

Take the \( x \) terms:

\[
x^2 - 16x
\]

To complete the square, take half of \(-16\) (which is \(-8\)), square it to get \(64\), and rewrite:

\[
x^2 - 16x + 64 - 64
\]

This simplifies to:

\[
(x - 8)^2 - 64
\]

### Step 3: Completing the square for \( y \)

Now take the \( y \) terms:

\[
y^2 - 6y
\]

Take half of \(-6\) (which is \(-3\)), square it to get \(9\), and rewrite:

\[
y^2 - 6y + 9 - 9
\]

This simplifies to:

\[
(y - 3)^2 - 9
\]

### Step 4: Putting it all together

Now substitute back into the equation:

\[
(x - 8)^2 - 64 + (y - 3)^2 - 9 = -24
\]

Combine constants on the left-hand side:

\[
(x - 8)^2 + (y - 3)^2 - 73 = -24
\]

Bring \(-73\) to the right side:

\[
(x - 8)^2 + (y - 3)^2 = -24 + 73
\]

This simplifies to:

\[
(x - 8)^2 + (y - 3)^2 = 49
\]

### Step 5: Determine center and radius

From the final equation \((x - 8)^2 + (y - 3)^2 = 49\):

- The center of the circle is \((8, 3)\).
- The radius is \(\sqrt{49} = 7\).

Thus, the center and radius of the circle are:

center = (8, 3), radius = 7

So the correct response is:

**center=(8,3), radius=7**

Related Questions