What is the relative frequency of students who prefer cats who are 8th graders? Round the percentage to the nearest tenth.

Given:
Preference: cats, dogs, no preference
7th graders: 36,8,2
8th graders: 22,26,6

A. 26%
b. 30.7%
C. 37.9
D. 48%

1 answer

To find the relative frequency of 8th graders who prefer cats, we first need to determine the total number of 8th graders surveyed and then calculate the percentage of those who prefer cats.

From the data given for 8th graders:

  • Preference for cats: 22
  • Preference for dogs: 26
  • No preference: 6

Now we calculate the total number of 8th graders: \[ \text{Total for 8th graders} = \text{Cats} + \text{Dogs} + \text{No preference} = 22 + 26 + 6 = 54 \]

Next, to find the relative frequency of 8th graders who prefer cats: \[ \text{Relative frequency} = \frac{\text{Number of 8th graders who prefer cats}}{\text{Total number of 8th graders}} = \frac{22}{54} \]

Now we convert this fraction to a percentage: \[ \frac{22}{54} \approx 0.4074 \text{ (keeping 4 decimal places)} \] \[ 0.4074 \times 100 \approx 40.74% \]

Rounding this to the nearest tenth gives us: \[ \approx 40.7% \]

Thus, none of the answer choices provided (26%, 30.7%, 37.9%, 48%) match the calculated relative frequency of 40.7%.

However, revisiting the percentages, let's check again with the options for possible calculations.

  1. 22 out of 54:
    • \[ \frac{22}{54} \approx 0.4074 \text{ rounds to } 40.7%\]

If the intent was for different grade levels, clarify the question around the totals or data interpretation, as the clearly defined calculation arrives at 40.7%, but none of the options aligns.

In conclusion, please confirm whether there are additional elements or clarifications necessary to proceed with any further calculations.