Question

Question
Use the table to answer the question.

The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier.
Outcome K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K
, I
, N
, D
. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)
Responses

0.24
0.24

0.72
0.72

0.45
0.45

0.28

Answer 1

To find the probability of the spinner landing on a consonant, we first need to identify the consonants from the letters given.

The letters on the spinner are:
- K (consonant)
- I (vowel)
- N (consonant)
- D (consonant)

The consonants are K, N, and D. Therefore, there are 3 consonants.

Next, we find the total frequency of the outcomes:
- K: 120
- I: 140
- N: 105
- D: 135

Total frequency = 120 + 140 + 105 + 135 = 500

Now we add the frequencies of the consonants:
- K: 120
- N: 105
- D: 135

Total frequency of consonants = 120 + 105 + 135 = 360

Now we can calculate the probability of landing on a consonant:
Probability of landing on a consonant = (Total frequency of consonants) / (Total frequency of all outcomes)
= 360 / 500
= 0.72

Thus, the approximate probability that the spinner will stop on a consonant on the next spin is:

**0.72**.