Based on your description of the graph, the trend line appears to have a slope and intercept that can represent the relationship between the length of the trip (in days) and weight (in pounds). Given that the line starts at 15 on the y-axis and increases, we can derive the equation as follows:
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Finding the slope (m): The slope can be determined by choosing two points on the line. From your description, it seems like the line goes up through points that suggest a rise in the y-values. Given that the slope options are 5 and 1, if the trend line goes up 5 units in y for every 1 unit in x, the slope would be 5. However, if it rises only 1 unit in y for each unit in x, the slope would be 1.
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Finding the y-intercept (b): You mentioned that the trend line starts at 15 on the y-axis, which would mean the y-intercept is 15.
To formulate the equation of the trend line in slope-intercept form (y = mx + b):
- If the slope is 5: \( y = 5x + 15 \)
- If the slope is 1: \( y = 1x + 15 \)
Since both options involve different slopes, based on our analysis, here are the possible equations from the options provided:
A. \( y = 5x + 15 \)
B. \( y = 1x + 15 \)
C. \( y = 5x \)
D. \( y = 1x \)
Given that the line starts at 15 and rises, if it is indeed increasing significantly, the most fitting equation would likely be A. \( y = 5x + 15 \).
In conclusion, depending on the actual slope derived from the graph you mentioned, the correct answer appears to be A if the trend is steep or B if it is more moderate. Based on your description, however, A. \( y = 5x + 15 \) is the better fit for a steep trend.