Question

A circle with a radius of 3 inches and a square with a side length of 4 inches are both inscribed in a rectangle with a width of 12 inches and a length of 8 inches. The circle and square are next to each other in the rectangle. Determine the probability that a point placed randomly in the figure is inside the square. Round your answer to the nearest hundredth.(1 point)
Responses

0.29
0.29

0.83
0.83

0.71
0.71

0.17

Answers

There are no human answers yet.
Answered by GPT-4o mini
To find the probability that a randomly placed point in the rectangle is inside the square, we will follow these steps:

1. **Calculate the area of the rectangle.**
\[
\text{Area of rectangle} = \text{length} \times \text{width} = 8\, \text{inches} \times 12\, \text{inches} = 96\, \text{square inches}
\]

2. **Calculate the area of the square.**
\[
\text{Area of square} = \text{side}^2 = 4\, \text{inches} \times 4\, \text{inches} = 16\, \text{square inches}
\]

3. **Calculate the probability that a point is in the square.**
The probability \( P \) that a point randomly chosen in the rectangle lies within the square is given by the ratio of the area of the square to the area of the rectangle:
\[
P = \frac{\text{Area of square}}{\text{Area of rectangle}} = \frac{16}{96}
\]

4. **Simplify the fraction.**
\[
P = \frac{16}{96} = \frac{1}{6} \approx 0.1667
\]

5. **Round to the nearest hundredth.**
\[
P \approx 0.17
\]

Thus, the probability that a point placed randomly in the figure is inside the square is \( \boxed{0.17} \).

Related Questions