A circle with a radius of 4 centimeters is inscribed in a square with a side length of 8 centimeters. What is the probability that a point placed randomly in the figure will be inside the circle? Round your answer to the nearest hundredth.(1 point)

1 answer

To find the probability that a point placed randomly in the figure (the square) will be inside the circle, we need to calculate the areas of both the circle and the square.

  1. Area of the circle: The formula for the area \(A\) of a circle is given by:

    \[ A = \pi r^2 \]

    where \(r\) is the radius. Here, the radius \(r = 4\) cm.

    \[ A_{\text{circle}} = \pi (4^2) = \pi \times 16 = 16\pi \]

  2. Area of the square: The formula for the area \(A\) of a square is given by:

    \[ A = s^2 \]

    where \(s\) is the side length. Here, the side length \(s = 8\) cm.

    \[ A_{\text{square}} = 8^2 = 64 \]

  3. Probability of selecting a point inside the circle: The probability \(P\) is given by the ratio of the area of the circle to the area of the square.

    \[ P = \frac{A_{\text{circle}}}{A_{\text{square}}} = \frac{16\pi}{64} = \frac{\pi}{4} \]

    Using the approximate value of \(\pi \approx 3.14\):

    \[ P \approx \frac{3.14}{4} \approx 0.785 \]

  4. Rounding to the nearest hundredth: We round \(0.785\) to:

    \[ 0.79 \]

Thus, the probability that a randomly placed point in the square will be inside the circle is:

\[ \boxed{0.79} \]