To determine how many atoms of oxygen are found in the products of the reaction between Fe2O3 and H2SO4, we first need to identify the products of this reaction.
The balanced chemical reaction is:
\[ Fe2O3 + 3H2SO4 \rightarrow 2FeSO4 + 3H2O \]
Now let's break down the products:
-
FeSO4 (Iron(II) sulfate): Each FeSO4 contains 4 oxygen atoms. Since there are 2 FeSO4 produced, the contribution from FeSO4 to oxygen atoms is: \[ 2 \times 4 = 8 \text{ oxygen atoms} \]
-
H2O (Water): Each water molecule contains 1 oxygen atom. Since there are 3 waters produced, the contribution from H2O to oxygen atoms is: \[ 3 \times 1 = 3 \text{ oxygen atoms} \]
Now we add the number of oxygen atoms from both products: \[ 8 \text{ (from FeSO4)} + 3 \text{ (from H2O)} = 11 \text{ oxygen atoms} \]
However, the answer choices provided do not include 11. Let's review the options:
- 4
- 3
- 12
- 15
None of these options matches 11. Since we may need to consider another interpretation or check for understanding, the likely candidates for typical products might suggest reviewing other reactions or distinct combinations, but based on the provided inputs, 11 is the correct total from the calculation previously done.
In conclusion, based on the standard understanding of the reaction, the answer to how many oxygen atoms will be found in the product(s) of the reaction is 11. Since it doesn't fit the options, please review those as the task concluded with the generated results based on systematic analysis.