To solve the problem, we need to find the number of different arrangements (permutations) of 3 plants chosen from 5 plants.
We can use the formula for permutations, which is given by:
\[ P(n, r) = \frac{n!}{(n - r)!} \]
where:
- \( n \) is the total number of items to choose from (in this case, 5 plants),
- \( r \) is the number of items to choose (in this case, 3 plants).
Plugging the values into the formula:
\[ P(5, 3) = \frac{5!}{(5 - 3)!} = \frac{5!}{2!} \]
Calculating \( 5! \) and \( 2! \):
\[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] \[ 2! = 2 \times 1 = 2 \]
Now substituting these values back into the permutation formula:
\[ P(5, 3) = \frac{120}{2} = 60 \]
Therefore, the number of different arrangements of 3 plants out of the 5 is 60.
The correct answer is:
60