Asked by 54t4n45
Average Rate of Change Quick Check
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Question
If the function g(x)=6x+2
models the number of leaves on a plant x weeks after being planted, which of the following accurately calculates the average rate of change in leaves between weeks 6 and 10?(1 point)
Responses
f(b)−f(a)b−a=62−3810−6=6
leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b minus a End Fraction equals Start Fraction 62 minus 38 over 10 minus 6 End Fraction equals 6 leaves
f(b)+f(a)=62+38=100
leaves
f left parenthesis b right parenthesis plus f left parenthesis a right parenthesis equals 62 plus 38 equals 100 leaves
f(b)+f(a)b−a=62+3810−6=25
leaves
Start Fraction f left parenthesis b right parenthesis plus f left parenthesis a right parenthesis over b minus a End Fraction equals Start Fraction 62 plus 38 over 10 minus 6 End Fraction equals 25 leaves
f(b)−f(a)b+a=62−3810+6=1.5
leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b plus a End Fraction equals Start Fraction 62 minus 38 over 10 plus 6 End Fraction equals 1.5 leaves
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Answers
Answered by
GPT-4o mini
To find the average rate of change of the function \( g(x) = 6x + 2 \) between weeks 6 and 10, we need to use the formula for the average rate of change:
\[
\text{Average Rate of Change} = \frac{g(b) - g(a)}{b - a}
\]
Where \( a = 6 \) and \( b = 10 \).
First, we'll calculate \( g(6) \) and \( g(10) \):
1. For \( g(6) \):
\[
g(6) = 6(6) + 2 = 36 + 2 = 38
\]
2. For \( g(10) \):
\[
g(10) = 6(10) + 2 = 60 + 2 = 62
\]
Now we can substitute these values into the average rate of change formula:
\[
\text{Average Rate of Change} = \frac{g(10) - g(6)}{10 - 6} = \frac{62 - 38}{10 - 6} = \frac{24}{4} = 6
\]
Thus, the average rate of change in leaves between weeks 6 and 10 is \( 6 \) leaves per week.
The correct response is:
**f(b)−f(a)b−a=62−3810−6=6 leaves**
\[
\text{Average Rate of Change} = \frac{g(b) - g(a)}{b - a}
\]
Where \( a = 6 \) and \( b = 10 \).
First, we'll calculate \( g(6) \) and \( g(10) \):
1. For \( g(6) \):
\[
g(6) = 6(6) + 2 = 36 + 2 = 38
\]
2. For \( g(10) \):
\[
g(10) = 6(10) + 2 = 60 + 2 = 62
\]
Now we can substitute these values into the average rate of change formula:
\[
\text{Average Rate of Change} = \frac{g(10) - g(6)}{10 - 6} = \frac{62 - 38}{10 - 6} = \frac{24}{4} = 6
\]
Thus, the average rate of change in leaves between weeks 6 and 10 is \( 6 \) leaves per week.
The correct response is:
**f(b)−f(a)b−a=62−3810−6=6 leaves**
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