Average Rate of Change Quick Check

3 of 53 of 5 Items

Question
If the function g(x)=6x+2
models the number of leaves on a plant x weeks after being planted, which of the following accurately calculates the average rate of change in leaves between weeks 6 and 10?(1 point)
Responses

f(b)−f(a)b−a=62−3810−6=6
leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b minus a End Fraction equals Start Fraction 62 minus 38 over 10 minus 6 End Fraction equals 6 leaves

f(b)+f(a)=62+38=100
leaves
f left parenthesis b right parenthesis plus f left parenthesis a right parenthesis equals 62 plus 38 equals 100 leaves

f(b)+f(a)b−a=62+3810−6=25
leaves
Start Fraction f left parenthesis b right parenthesis plus f left parenthesis a right parenthesis over b minus a End Fraction equals Start Fraction 62 plus 38 over 10 minus 6 End Fraction equals 25 leaves

f(b)−f(a)b+a=62−3810+6=1.5
leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b plus a End Fraction equals Start Fraction 62 minus 38 over 10 plus 6 End Fraction equals 1.5 leaves
Skip to navigation

1 answer

To find the average rate of change of the function \( g(x) = 6x + 2 \) between weeks 6 and 10, we need to use the formula for the average rate of change:

\[ \text{Average Rate of Change} = \frac{g(b) - g(a)}{b - a} \]

Where \( a = 6 \) and \( b = 10 \).

First, we'll calculate \( g(6) \) and \( g(10) \):

  1. For \( g(6) \): \[ g(6) = 6(6) + 2 = 36 + 2 = 38 \]

  2. For \( g(10) \): \[ g(10) = 6(10) + 2 = 60 + 2 = 62 \]

Now we can substitute these values into the average rate of change formula:

\[ \text{Average Rate of Change} = \frac{g(10) - g(6)}{10 - 6} = \frac{62 - 38}{10 - 6} = \frac{24}{4} = 6 \]

Thus, the average rate of change in leaves between weeks 6 and 10 is \( 6 \) leaves per week.

The correct response is:

f(b)−f(a)b−a=62−3810−6=6 leaves