A water treatment plant is built with three cylindrical tanks to contain the water for a town. Each tank has a radius of 15 feet and a depth of 22 feet.

If there are about 7.5 gallons in a cubic foot of​ water, approximately how many gallons of water can be treated at the plant at any one​ time?
Question content area bottom
Part 1
A.3.5 times 10 Superscript 5
3.5 times 10 Superscript 5
B.1.2 times 10 Superscript 5
1.2 times 10 Superscript 5
C.3.5 times 10 Superscript 6
3.5 times 10 Superscript 6
D.6.2 times 10 cubed
6.2 times 10 cubed

1 answer

To find out how many gallons of water can be treated at the plant at any one time, we first need to calculate the volume of one cylindrical tank and then find the total volume for three tanks.

Step 1: Calculate the volume of one cylindrical tank

The formula for the volume \( V \) of a cylinder is given by:

\[ V = \pi r^2 h \]

where:

  • \( r \) is the radius of the cylinder,
  • \( h \) is the height (or depth) of the cylinder.

Given:

  • Radius \( r = 15 \) feet,
  • Height \( h = 22 \) feet.

Now, substituting these values into the formula:

\[ V = \pi (15)^2 (22) \] \[ V = \pi (225) (22) = 4950\pi \text{ cubic feet} \]

Step 2: Calculate the total volume for three tanks

We have three tanks, so we multiply the volume of one tank by 3:

\[ \text{Total Volume} = 3 \times 4950\pi = 14850\pi \text{ cubic feet} \]

Step 3: Calculate the total volume in gallons

Since there are about 7.5 gallons in a cubic foot, we can find the total gallons:

\[ \text{Total Gallons} = 14850\pi \times 7.5 \]

First, we need to calculate \( 14850 \times 7.5 \):

\[ 14850 \times 7.5 = 111375 \]

Now, using \( \pi \approx 3.14 \):

\[ \text{Total Gallons} \approx 111375 \times 3.14 \approx 349,493.75 \]

Conclusion

We round 349,493.75 to the nearest whole number:

  • Approximately \( 349,494 \) gallons.

Now let's express this in scientific notation:

\[ 349,494 \approx 3.49494 \times 10^5 \approx 3.5 \times 10^5 \]

Final Answer

The correct choice is:

A. \( 3.5 \times 10^5 \)