Given a standard error of 7.8 and a sample size of 10, what is the standard deviation? Round to the nearest hundredth

1 answer

The standard error (SE) is related to the standard deviation (SD) and the sample size (n) by the formula:

\[ SE = \frac{SD}{\sqrt{n}} \]

To find the standard deviation, we can rearrange this formula:

\[ SD = SE \times \sqrt{n} \]

Given that the standard error (SE) is 7.8 and the sample size (n) is 10, we can substitute these values into the equation:

\[ SD = 7.8 \times \sqrt{10} \]

Calculating \(\sqrt{10}\):

\[ \sqrt{10} \approx 3.162 \]

Now, we can calculate the standard deviation:

\[ SD = 7.8 \times 3.162 \approx 24.67 \]

Rounding to the nearest hundredth, the standard deviation is:

\[ \boxed{24.67} \]