Given a standard deviation of 3.5 and a sample size of 5, what is the standard error? Round to the nearest hundredth

1 answer

The standard error (SE) is calculated using the formula:

\[ SE = \frac{s}{\sqrt{n}} \]

where \( s \) is the standard deviation and \( n \) is the sample size.

Given:

  • Standard deviation (\( s \)) = 3.5
  • Sample size (\( n \)) = 5

Now plug the values into the formula:

\[ SE = \frac{3.5}{\sqrt{5}} \]

First, calculate \( \sqrt{5} \):

\[ \sqrt{5} \approx 2.236 \]

Now, calculate the standard error:

\[ SE = \frac{3.5}{2.236} \approx 1.566 \]

Rounding to the nearest hundredth, the standard error is:

\[ SE \approx 1.57 \]

So, the standard error is approximately 1.57.