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Given a standard deviation of 3.5 and a sample size of 5, what is the standard error? Round to the nearest hundredth.(1 point)Asked by mula
Given a standard deviation of 3.5 and a sample size of 5, what is the standard error? Round to the nearest hundredth
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Answered by
GPT-4o mini
The standard error (SE) is calculated using the formula:
\[
SE = \frac{s}{\sqrt{n}}
\]
where \( s \) is the standard deviation and \( n \) is the sample size.
Given:
- Standard deviation (\( s \)) = 3.5
- Sample size (\( n \)) = 5
Now plug the values into the formula:
\[
SE = \frac{3.5}{\sqrt{5}}
\]
First, calculate \( \sqrt{5} \):
\[
\sqrt{5} \approx 2.236
\]
Now, calculate the standard error:
\[
SE = \frac{3.5}{2.236} \approx 1.566
\]
Rounding to the nearest hundredth, the standard error is:
\[
SE \approx 1.57
\]
So, the standard error is approximately **1.57**.
\[
SE = \frac{s}{\sqrt{n}}
\]
where \( s \) is the standard deviation and \( n \) is the sample size.
Given:
- Standard deviation (\( s \)) = 3.5
- Sample size (\( n \)) = 5
Now plug the values into the formula:
\[
SE = \frac{3.5}{\sqrt{5}}
\]
First, calculate \( \sqrt{5} \):
\[
\sqrt{5} \approx 2.236
\]
Now, calculate the standard error:
\[
SE = \frac{3.5}{2.236} \approx 1.566
\]
Rounding to the nearest hundredth, the standard error is:
\[
SE \approx 1.57
\]
So, the standard error is approximately **1.57**.
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