Question

Jen graphs y = −



Jen graphs.y=-\frac{1}{2}x+8 Which point is on the line?

Answer 1

To determine which point is on the line represented by the equation \( y = -\frac{1}{2}x + 8 \), we can select various points and check if they satisfy the equation.

Instead of selecting points directly, let's solve for specific \( x \) values to find corresponding \( y \) values:

1. **If \( x = 0 \)**:
\[
y = -\frac{1}{2}(0) + 8 = 8
\]
So one point on the line is \( (0, 8) \).

2. **If \( x = 2 \)**:
\[
y = -\frac{1}{2}(2) + 8 = -1 + 8 = 7
\]
So another point on the line is \( (2, 7) \).

3. **If \( x = 4 \)**:
\[
y = -\frac{1}{2}(4) + 8 = -2 + 8 = 6
\]
So another point on the line is \( (4, 6) \).

4. **If \( x = 8 \)**:
\[
y = -\frac{1}{2}(8) + 8 = -4 + 8 = 4
\]
So another point on the line is \( (8, 4) \).

5. **If \( x = 16 \)**:
\[
y = -\frac{1}{2}(16) + 8 = -8 + 8 = 0
\]
So another point on the line is \( (16, 0) \).

Now, any of these points \( (0, 8) \), \( (2, 7) \), \( (4, 6) \), \( (8, 4) \), or \( (16, 0) \) would be valid points on the line. If you have specific options to choose from, please provide them, and we can verify which is on the line.