The incorrect step in Misha's proof is Step 3.
Misha assumes that since lines \( l \) and \( n \) are not parallel, they must intersect at some point. However, if two lines are not parallel, it can imply that they intersect; but if they share the same slope and are distinct (as stated), they cannot intersect at any point, because parallel lines never intersect by definition.
Thus, the statement in Step 3 is flawed, because distinct lines with the same slope cannot intersect regardless of any conditions.
Therefore, the correct response is: Step 3 is incorrect. The lines do not need to have a point of intersection since they are not parallel.