Question
Identify the multiplicities of the linear factors of h(x)=(x+4)(x−1)2(x+3)5
ℎ
(
𝑥
)
=
(
𝑥
+
4
)
(
𝑥
−
1
)
2
(
𝑥
+
3
)
5
.(1 point)
Responses

The multiplicity of (x+4)
(
𝑥
+
4
)
is 4, the multiplicity of (x−1)
(
𝑥
−
1
)
is −1
−
1
, and the multiplicity of (x+3)
(
𝑥
+
3
)
is 3.
The multiplicity of left parenthesis x plus 4 right parenthesis is 4, the multiplicity of left parenthesis x minus 1 right parenthesis is negative 1 , and the multiplicity of left parenthesis x plus 3 right parenthesis is 3.

The multiplicity of (x+4)
(
𝑥
+
4
)
is −4
−
4
, the multiplicity of (x−1)
(
𝑥
−
1
)
is 1, and the multiplicity of (x+3)
(
𝑥
+
3
)
is −3
−
3
.
The multiplicity of left parenthesis x plus 4 right parenthesis is negative 4 , the multiplicity of left parenthesis x minus 1 right parenthesis is 1, and the multiplicity of left parenthesis x plus 3 right parenthesis is negative 3 .

The multiplicity of (x+4)
(
𝑥
+
4
)
is 1, the multiplicity of (x−1)
(
𝑥
−
1
)
is 2, and the multiplicity of (x+3)
(
𝑥
+
3
)
is 5.
The multiplicity of left parenthesis x plus 4 right parenthesis is 1, the multiplicity of left parenthesis x minus 1 right parenthesis is 2, and the multiplicity of left parenthesis x plus 3 right parenthesis is 5.

The multiplicity of (x+4)
(
𝑥
+
4
)
is 0, the multiplicity of (x−1)
(
𝑥
−
1
)
is 2, and the multiplicity of (x+3)
(
𝑥
+
3
)
is 5.
ℎ
(
𝑥
)
=
(
𝑥
+
4
)
(
𝑥
−
1
)
2
(
𝑥
+
3
)
5
.(1 point)
Responses

The multiplicity of (x+4)
(
𝑥
+
4
)
is 4, the multiplicity of (x−1)
(
𝑥
−
1
)
is −1
−
1
, and the multiplicity of (x+3)
(
𝑥
+
3
)
is 3.
The multiplicity of left parenthesis x plus 4 right parenthesis is 4, the multiplicity of left parenthesis x minus 1 right parenthesis is negative 1 , and the multiplicity of left parenthesis x plus 3 right parenthesis is 3.

The multiplicity of (x+4)
(
𝑥
+
4
)
is −4
−
4
, the multiplicity of (x−1)
(
𝑥
−
1
)
is 1, and the multiplicity of (x+3)
(
𝑥
+
3
)
is −3
−
3
.
The multiplicity of left parenthesis x plus 4 right parenthesis is negative 4 , the multiplicity of left parenthesis x minus 1 right parenthesis is 1, and the multiplicity of left parenthesis x plus 3 right parenthesis is negative 3 .

The multiplicity of (x+4)
(
𝑥
+
4
)
is 1, the multiplicity of (x−1)
(
𝑥
−
1
)
is 2, and the multiplicity of (x+3)
(
𝑥
+
3
)
is 5.
The multiplicity of left parenthesis x plus 4 right parenthesis is 1, the multiplicity of left parenthesis x minus 1 right parenthesis is 2, and the multiplicity of left parenthesis x plus 3 right parenthesis is 5.

The multiplicity of (x+4)
(
𝑥
+
4
)
is 0, the multiplicity of (x−1)
(
𝑥
−
1
)
is 2, and the multiplicity of (x+3)
(
𝑥
+
3
)
is 5.
Answers
Answered by
GPT-4o mini
To identify the multiplicities of the linear factors in the polynomial \( h(x) = (x + 4)(x - 1)^2(x + 3)^5 \), we analyze each factor:
1. The factor \( (x + 4) \) appears once, so its multiplicity is **1**.
2. The factor \( (x - 1) \) appears squared, so its multiplicity is **2**.
3. The factor \( (x + 3) \) appears raised to the fifth power, so its multiplicity is **5**.
Putting it all together:
- The multiplicity of \( (x + 4) \) is **1**.
- The multiplicity of \( (x - 1) \) is **2**.
- The multiplicity of \( (x + 3) \) is **5**.
Therefore, the correct response is:
**The multiplicity of \( (x + 4) \) is 1, the multiplicity of \( (x - 1) \) is 2, and the multiplicity of \( (x + 3) \) is 5.**
1. The factor \( (x + 4) \) appears once, so its multiplicity is **1**.
2. The factor \( (x - 1) \) appears squared, so its multiplicity is **2**.
3. The factor \( (x + 3) \) appears raised to the fifth power, so its multiplicity is **5**.
Putting it all together:
- The multiplicity of \( (x + 4) \) is **1**.
- The multiplicity of \( (x - 1) \) is **2**.
- The multiplicity of \( (x + 3) \) is **5**.
Therefore, the correct response is:
**The multiplicity of \( (x + 4) \) is 1, the multiplicity of \( (x - 1) \) is 2, and the multiplicity of \( (x + 3) \) is 5.**
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