Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5

. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

0 feet above or below
0 feet above or below

5 feet below
5 feet below

5 feet above
5 feet above

2.5 feet below

1 answer

In the formula you provided, \( y = -16t^2 + 40t - 5 \), the variable \( y \) represents the height above or below street level at time \( t \), where \( t \) is measured in seconds.

To determine how far below or above street level Luca's initial launching point is, we need to evaluate the function at \( t = 0 \):

\[ y(0) = -16(0)^2 + 40(0) - 5 \] \[ y(0) = -5 \]

This means that Luca’s initial launching point is 5 feet below street level.

Therefore, the correct response is:

5 feet below.