Which of the following uses the properties of logarithms to correctly evaluate log1023 ?(1 point) Responses log1023=−23 logarithm 10 superscript 23 baseline equals negative 23 log1023=10−23 logarithm 10 superscript 23 baseline equals 10 superscript negative 23 baseline log1023=23 logarithm 10 superscript 23 baseline equals 23 log1023=1023

1 answer

To evaluate \(\log_{10}(23)\), we should remember the basic property of logarithms:

  1. \(\log_{b}(b) = 1\) for any base \(b\),
  2. \(\log_{b}(1) = 0\) for any base \(b\),
  3. \(\log_{b}(a \cdot c) = \log_{b}(a) + \log_{b}(c)\),
  4. \(\log_{b}(a/c) = \log_{b}(a) - \log_{b}(c)\),
  5. \(\log_{b}(a^n) = n \cdot \log_{b}(a)\).

None of the given options correctly apply the logarithmic properties to evaluate \(\log_{10}(23)\).

In fact, \(\log_{10}(23)\) is simply a specific value that does not simplify nicely to any of the options given. Therefore, none of the responses (such as \(-23\), \(10^{-23}\), \(23\), or \(1023\)) correctly evaluate \(\log_{10}(23)\).

If you were looking to calculate or approximate \(\log_{10}(23)\), it would usually be done using a calculator, yielding approximately \(1.362\).