Asked by paulina
I need help sovling this. It is a fraction.
+5/x-1 + 2-x/x
I hope that you can understand what I wrote. Someone please help because I am new at this. Help!!!!
+5/x-1 + 2-x/x
I hope that you can understand what I wrote. Someone please help because I am new at this. Help!!!!
Answers
Answered by
Tom
First find a common denominator
This common denominator will be
(x)(x-1)
then since the denominator of 5/(x-1) is missing x multiply x to 5 to get 5x.
since the denominator of (2-x)/x is missing (x-1) multiply (2-x) with (x-1) to get (2-x)(x-1)
Now add the numerators and put them over the denominator
5x+(2-x)(x-1) / x(x-1)
Now this needs to be cleaned up:
(2-x)(x-1) = -x^2 + 3x-2
-x^2 + 3x-2 +5x = -x^2+8x-2 for the numerator
There is no way to factor this neatly, so we will leave it as a quadratic and put it over the denominator which is already simplified.
SOLUTION:
-x^2+8x-2 / / x(x-1)
This common denominator will be
(x)(x-1)
then since the denominator of 5/(x-1) is missing x multiply x to 5 to get 5x.
since the denominator of (2-x)/x is missing (x-1) multiply (2-x) with (x-1) to get (2-x)(x-1)
Now add the numerators and put them over the denominator
5x+(2-x)(x-1) / x(x-1)
Now this needs to be cleaned up:
(2-x)(x-1) = -x^2 + 3x-2
-x^2 + 3x-2 +5x = -x^2+8x-2 for the numerator
There is no way to factor this neatly, so we will leave it as a quadratic and put it over the denominator which is already simplified.
SOLUTION:
-x^2+8x-2 / / x(x-1)
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