Question

13. A food truck only sells cheese pizza slices and pepperoni pizza slices. During the lunch rush, the food truck owner prepares more than 60
slices of pizza and earns no more than $268.75.
• Cheese pizza slices cost $3.75.
• Pepperoni pizza slices cost $4.50. If x represents the number of cheese pizza slices sold and y represents the number of pepperoni pizza slices sold, which system of inequalities
represents the scenario?
A 3.75x + 4.50y < 60
x+ y ≥ 268.75
3.75x + 4.50y > 60
x+ y≤ 268.75
c 3.75x + 4.50y = 268.75
x+y< 60
3.75x + 4.50y ≤ 268.75x+ y> 60

Answer 1

To represent the given scenario with an appropriate system of inequalities, we need to consider the two conditions provided: the total number of pizza slices and the total earnings.

1. **Total Slices**: The food truck prepares more than 60 slices of pizza.
- This can be represented by the inequality:
\[
x + y > 60
\]

2. **Total Earnings**: The food truck earns no more than $268.75.
- Since the cost of cheese pizza slices is $3.75 each (x slices) and pepperoni slices is $4.50 each (y slices), the total earnings can be represented by:
\[
3.75x + 4.50y ≤ 268.75
\]

Putting these inequalities together, we have the system:
\[
\begin{align*}
x + y & > 60 \\
3.75x + 4.50y & ≤ 268.75
\end{align*}
\]

Therefore, the correct system of inequalities representing the scenario is:
\[
\begin{align*}
1. & \quad x + y > 60 \\
2. & \quad 3.75x + 4.50y ≤ 268.75
\end{align*}
\]

Just to clarify, neither of the options labeled A, B, or C matches the correct representation exactly with the correct inequalities.

So, the system that represents the situation is:
1. \( x + y > 60 \)
2. \( 3.75x + 4.50y \leq 268.75 \)