A student purified a 3.88 g sample of phthalic acid by recrystallization from water. The published solubility of phthalic acid in 100 mL of water is 0.54 g at 14ºC and 18 g at 99ºC. What is the smallest volume (in milliliters) of boiling water the student could use to dissolve the 3.88 g sample of phthalic acid? (Report your answer to 3 significant figures.)
3 answers
100 mL x 3.88g/18g = ?? mL at 99 C. We will assume that is at 100.
718
13.2ml