An image displaying a line LM with vertices L of -7 comma -2 and M of 0 comma 5 and L'M' with vertices L' of -2 comma 0 and M' of 5 comma 7.

A.
(x, y) → (x + 5, y + 2)
B.
(x, y) → (x – 7, y – 2)
C.
(x, y) → (x – 5, y – 2)
D.
(x, y) → (x + 2, y + 5)

1 answer

To determine how the line segment LM with vertices \(L(-7, -2)\) and \(M(0, 5)\) is transformed to line segment \(L'M'\) with vertices \(L'(-2, 0)\) and \(M'(5, 7)\), we can calculate the transformation needed to map the coordinates of \(L\) and \(M\) to \(L'\) and \(M'\).

  1. Finding the transformation for point \(L\):

    • Original point \(L(-7, -2)\)
    • After transformation \(L'(-2, 0)\)

    Let's find the change in each coordinate:

    • For \(x\): \(-7\) is transformed to \(-2\). The change is: \[ -2 - (-7) = -2 + 7 = 5 \]
    • For \(y\): \(-2\) is transformed to \(0\). The change is: \[ 0 - (-2) = 0 + 2 = 2 \]

    Therefore, the transformation for point \(L\) can be described by the function: \[ (x, y) \rightarrow (x + 5, y + 2) \]

  2. Finding the transformation for point \(M\):

    • Original point \(M(0, 5)\)
    • After transformation \(M'(5, 7)\)

    Let's find the change in each coordinate:

    • For \(x\): \(0\) is transformed to \(5\). The change is: \[ 5 - 0 = 5 \]
    • For \(y\): \(5\) is transformed to \(7\). The change is: \[ 7 - 5 = 2 \]

    This confirms that the transformation for point \(M\) agrees with the transformation found for point \(L\).

Conclusion

The transformation that maps line segment LM to L'M' is represented by: \[ \text{(x, y) } \rightarrow \text{ (x + 5, y + 2)} \] Thus, the correct answer is Option A.