To find the volume of a cylindrical can, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
Where:
- \(V\) is the volume,
- \(r\) is the radius of the cylinder,
- \(h\) is the height of the cylinder,
- \(\pi\) is a constant (approximately 3.14 as specified).
Given:
- Diameter of the can = 7 cm, so the radius \(r = \frac{diameter}{2} = \frac{7}{2} = 3.5\) cm,
- Height \(h = 11\) cm.
Now we can plug in the values into the volume formula:
\[ V = 3.14 \times (3.5)^2 \times 11 \] \[ V = 3.14 \times 12.25 \times 11 \] \[ V = 3.14 \times 134.75 \] \[ V \approx 422.645 \]
Rounding to the nearest cubic centimeter, we get:
\[ V \approx 423 \text{ cm}^3 \]
Therefore, the volume of the soup contained in the can is 423 cm³.
The correct answer is D. 423 cm³.