Question

A can of soup has a diameter of 7 cm and a height of 11 cm. Assuming that the can is full, what is the volume of soup contained in the can? Use 3.14 for π and round your answer to the nearest cubic centimeter.

The image depicts a cylindrical box of length eleven centimeters and width seven centimeters written with the words tomato soup.
A.
135 cm3
B.
242 cm3
C.
1692 cm3
D.
423 cm3

Answer 1

To find the volume of a cylindrical can, we can use the formula for the volume of a cylinder:

\[
V = \pi r^2 h
\]

Where:
- \(V\) is the volume,
- \(r\) is the radius of the cylinder,
- \(h\) is the height of the cylinder,
- \(\pi\) is a constant (approximately 3.14 as specified).

Given:
- Diameter of the can = 7 cm, so the radius \(r = \frac{diameter}{2} = \frac{7}{2} = 3.5\) cm,
- Height \(h = 11\) cm.

Now we can plug in the values into the volume formula:

\[
V = 3.14 \times (3.5)^2 \times 11
\]
\[
V = 3.14 \times 12.25 \times 11
\]
\[
V = 3.14 \times 134.75
\]
\[
V \approx 422.645
\]

Rounding to the nearest cubic centimeter, we get:

\[
V \approx 423 \text{ cm}^3
\]

Therefore, the volume of the soup contained in the can is **423 cm³**.

The correct answer is **D. 423 cm³**.