Question
Step by step formula writing of tetraoxosulphate (6)acid
Answers
GPT-4o mini
Tetraoxosulphate (VI) acid is more commonly known as sulfuric acid (H₂SO₄). It is a strong acid with significant industrial applications. Below is a step-by-step outline of how to derive the chemical formula for tetraoxosulphate (VI) acid.
### Step 1: Understanding the Name
- The name "tetraoxosulphate (VI)" indicates that the molecule contains:
- "tetra" meaning four oxygen atoms.
- "sulphate" refers to the presence of sulfur.
- "(VI)" indicates that sulfur is in the +6 oxidation state.
### Step 2: Determine the Central Atom
- The central atom in this compound is sulfur (S).
### Step 3: Count the Atoms
- According to the name, there are:
- 1 Sulfur (S)
- 4 Oxygen (O) atoms
- Additionally, sulfuric acid needs to be neutralized with hydrogen (H) ions to form the acid.
### Step 4: Hydrogen Atoms
- In sulfuric acid, there are 2 hydrogen atoms (H). This is because sulfuric acid can donate two protons (H⁺) in solution.
### Step 5: Combining the Atoms
- Putting it all together:
- Sulfur (S) = 1
- Oxygen (O) = 4
- Hydrogen (H) = 2
- This leads to the formula H₂SO₄.
### Step 6: Final Verification
- Check the oxidation states:
- Sulfur (S) in H₂SO₄ is in the +6 oxidation state, which is consistent with the "(VI)" designation.
- Each oxygen atom typically has a -2 oxidation state, resulting in a total of -8 for the four oxygen atoms.
- The overall charge balances as follows:
- 2 (from H) + 6 (from S) + (-8 from O) = 0, confirming the compound is neutral and the balance of charges is correct.
### Conclusion
The final chemical formula for tetraoxosulphate (VI) acid (sulfuric acid) is **H₂SO₄**.
### Step 1: Understanding the Name
- The name "tetraoxosulphate (VI)" indicates that the molecule contains:
- "tetra" meaning four oxygen atoms.
- "sulphate" refers to the presence of sulfur.
- "(VI)" indicates that sulfur is in the +6 oxidation state.
### Step 2: Determine the Central Atom
- The central atom in this compound is sulfur (S).
### Step 3: Count the Atoms
- According to the name, there are:
- 1 Sulfur (S)
- 4 Oxygen (O) atoms
- Additionally, sulfuric acid needs to be neutralized with hydrogen (H) ions to form the acid.
### Step 4: Hydrogen Atoms
- In sulfuric acid, there are 2 hydrogen atoms (H). This is because sulfuric acid can donate two protons (H⁺) in solution.
### Step 5: Combining the Atoms
- Putting it all together:
- Sulfur (S) = 1
- Oxygen (O) = 4
- Hydrogen (H) = 2
- This leads to the formula H₂SO₄.
### Step 6: Final Verification
- Check the oxidation states:
- Sulfur (S) in H₂SO₄ is in the +6 oxidation state, which is consistent with the "(VI)" designation.
- Each oxygen atom typically has a -2 oxidation state, resulting in a total of -8 for the four oxygen atoms.
- The overall charge balances as follows:
- 2 (from H) + 6 (from S) + (-8 from O) = 0, confirming the compound is neutral and the balance of charges is correct.
### Conclusion
The final chemical formula for tetraoxosulphate (VI) acid (sulfuric acid) is **H₂SO₄**.