Asked by uggs
Find the volume of a cone with a diameter of 12 m and a height of 6 m.
An image displaying a cone with a diameter of 12 metre and a height of 6 metre.
A.
288π m3
B.
216π m3
C.
72π m3
D.
72 m3
An image displaying a cone with a diameter of 12 metre and a height of 6 metre.
A.
288π m3
B.
216π m3
C.
72π m3
D.
72 m3
Answers
Answered by
GPT-4o mini
To find the volume of a cone, we can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( r \) is the radius of the base of the cone, and \( h \) is the height.
Given:
- The diameter of the cone is 12 m, so the radius \( r \) is half of the diameter:
\[
r = \frac{12}{2} = 6 \text{ m}
\]
- The height \( h \) is given as 6 m.
Now, we can substitute these values into the volume formula:
\[
V = \frac{1}{3} \pi (6)^2 (6)
\]
Calculating \( (6)^2 \):
\[
(6)^2 = 36
\]
Now substituting back into the volume formula:
\[
V = \frac{1}{3} \pi (36)(6)
\]
Calculating \( 36 \times 6 \):
\[
36 \times 6 = 216
\]
Now we have:
\[
V = \frac{1}{3} \pi (216)
\]
Calculating \( \frac{1}{3} \times 216 \):
\[
\frac{216}{3} = 72
\]
Thus, the volume of the cone is:
\[
V = 72\pi \text{ m}^3
\]
So the correct answer is:
C. \( 72\pi \text{ m}^3 \)
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( r \) is the radius of the base of the cone, and \( h \) is the height.
Given:
- The diameter of the cone is 12 m, so the radius \( r \) is half of the diameter:
\[
r = \frac{12}{2} = 6 \text{ m}
\]
- The height \( h \) is given as 6 m.
Now, we can substitute these values into the volume formula:
\[
V = \frac{1}{3} \pi (6)^2 (6)
\]
Calculating \( (6)^2 \):
\[
(6)^2 = 36
\]
Now substituting back into the volume formula:
\[
V = \frac{1}{3} \pi (36)(6)
\]
Calculating \( 36 \times 6 \):
\[
36 \times 6 = 216
\]
Now we have:
\[
V = \frac{1}{3} \pi (216)
\]
Calculating \( \frac{1}{3} \times 216 \):
\[
\frac{216}{3} = 72
\]
Thus, the volume of the cone is:
\[
V = 72\pi \text{ m}^3
\]
So the correct answer is:
C. \( 72\pi \text{ m}^3 \)