Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A BUS TRAVELS 280 KM SOUTH ALONG A STRAIGHT PATH WITH AN AVERAGE VELOCITY OF 88 KM/H TO THE SOUTH. THE BUS STOPS FOR 24MIN, THE...Asked by Jasmine
A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. The bus stops for 24 min. Then it travels 210 km south with an average velocity of 75 km/h to the south.
how long does the total trip last?
what is the average velocity for the total trip?
how long does the total trip last?
what is the average velocity for the total trip?
Answers
Answered by
Tom
280km / 88km per hour = 3.18 hours
+
24 minutes = .4 hours
+
210km / 75km per hour = 2.8 hours
2.8 hours + .4 hours + 3.18 hours = 6.38 hours
Average Velocity = Total Distance / time
Total distance = 280 + 210 = 490km
490km/6.38hours =76.8km per hour
+
24 minutes = .4 hours
+
210km / 75km per hour = 2.8 hours
2.8 hours + .4 hours + 3.18 hours = 6.38 hours
Average Velocity = Total Distance / time
Total distance = 280 + 210 = 490km
490km/6.38hours =76.8km per hour
Answered by
Jasmine
thankyou!
Answered by
Ree
Nice, Pretty easy to understand, thanks
Answered by
queen
A bus travels 445km south along a straight path with an average velocity of 90km/h to the south. The bus stops for 35 min. Then, it travels 321 km south with an average velocity of 83 km/h to the south. What is the average velocity for the total trip?
Answered by
jane
Given:-
d1=445km
V1=90km/h
d2=321km
V2=83km/h
and 35min = 0.58h
SOLUTION:
1) t= d/V = 445km / 90km/h = 4.9h (divide 445km by 90km/h)
t= d/V = 321km / 83km/h = 3.8h (divide 321km by 83km/h)
2) total time = 4.9h + 3.8h + 0.58h = 9.28h
3) Average velocity = total distance/time
= (445+321)/ 9.28
= 766/9.28 = 82.54km/h
[add both distance to get total distance, then divide by total time]
d1=445km
V1=90km/h
d2=321km
V2=83km/h
and 35min = 0.58h
SOLUTION:
1) t= d/V = 445km / 90km/h = 4.9h (divide 445km by 90km/h)
t= d/V = 321km / 83km/h = 3.8h (divide 321km by 83km/h)
2) total time = 4.9h + 3.8h + 0.58h = 9.28h
3) Average velocity = total distance/time
= (445+321)/ 9.28
= 766/9.28 = 82.54km/h
[add both distance to get total distance, then divide by total time]
Answered by
Zayed
Heather and Matthew walk with an average velocity of 0.98 m/s eastward. If it takes them 34 min to walk to the store, what is their displacement?
1999.8 m = 2 km 1999.2
1999.8 m = 2 km 1999.2
Answered by
Unknown
Thank you helped so much
There are no AI answers yet. The ability to request AI answers is coming soon!