Question
A box shaped like a right rectangular prism measures 8 inches by 6 inches by 5 inches. What is the length of the interior diagonal of the prism to the nearest hundredth?
10.77 inches
11.18 inches
10.68 inches
11.92 inches
10.77 inches
11.18 inches
10.68 inches
11.92 inches
Answers
GPT-4o mini
To find the length of the interior diagonal of a right rectangular prism, we can use the formula for the diagonal \( d \) of a prism:
\[
d = \sqrt{l^2 + w^2 + h^2}
\]
where:
- \( l \) is the length,
- \( w \) is the width, and
- \( h \) is the height of the prism.
In this case, the dimensions of the box are:
- \( l = 8 \) inches,
- \( w = 6 \) inches, and
- \( h = 5 \) inches.
Now we can substitute these values into the formula:
\[
d = \sqrt{8^2 + 6^2 + 5^2}
\]
Calculating each term:
\[
8^2 = 64
\]
\[
6^2 = 36
\]
\[
5^2 = 25
\]
Now, add these values together:
\[
64 + 36 + 25 = 125
\]
Next, we take the square root of 125:
\[
d = \sqrt{125}
\]
We can simplify \( \sqrt{125} \):
\[
\sqrt{125} = \sqrt{25 \cdot 5} = 5\sqrt{5}
\]
Now we need to calculate \( 5\sqrt{5} \). The approximate value of \( \sqrt{5} \) is about \( 2.236 \):
\[
d \approx 5 \times 2.236 \approx 11.18
\]
Thus, the length of the interior diagonal of the prism, to the nearest hundredth, is:
\[
\boxed{11.18} \text{ inches}
\]
\[
d = \sqrt{l^2 + w^2 + h^2}
\]
where:
- \( l \) is the length,
- \( w \) is the width, and
- \( h \) is the height of the prism.
In this case, the dimensions of the box are:
- \( l = 8 \) inches,
- \( w = 6 \) inches, and
- \( h = 5 \) inches.
Now we can substitute these values into the formula:
\[
d = \sqrt{8^2 + 6^2 + 5^2}
\]
Calculating each term:
\[
8^2 = 64
\]
\[
6^2 = 36
\]
\[
5^2 = 25
\]
Now, add these values together:
\[
64 + 36 + 25 = 125
\]
Next, we take the square root of 125:
\[
d = \sqrt{125}
\]
We can simplify \( \sqrt{125} \):
\[
\sqrt{125} = \sqrt{25 \cdot 5} = 5\sqrt{5}
\]
Now we need to calculate \( 5\sqrt{5} \). The approximate value of \( \sqrt{5} \) is about \( 2.236 \):
\[
d \approx 5 \times 2.236 \approx 11.18
\]
Thus, the length of the interior diagonal of the prism, to the nearest hundredth, is:
\[
\boxed{11.18} \text{ inches}
\]