Question

A baker has a container with 14
pound of blueberries. The baker wants to use an equal amount of blueberries on 8 desserts. How many blueberries will the baker use on each dessert?

Alex solves the problem by finding 14÷8.
Which shows another way to solve the problem?

(1 point)
Responses

14×8=2
pounds

1 4 × 8 = 2 pounds

14×18=132
pounds

1 4 × 1 8 = 1 32 pounds

4÷8=12
pounds

4 ÷ 8 = 1 2 pounds

4×8=12
pounds

1 answer

To find out how many pounds of blueberries the baker will use on each dessert, you need to divide the total amount of blueberries (14 pounds) by the number of desserts (8).

Alex correctly solves the problem by calculating \(14 \div 8\).

However, if we want to show another way to express this calculation, we can represent the total quantity being divided with fractions. For example, we could express the division using the equivalent fraction method.

One possible way to express it as a multiplication and see it in relation to the total amount is to consider the fractions involved:

If you were to express \(14 \div 8\) in fraction form it could be written as: \[ \frac{14}{8} \]

Then simplifying that fraction gives: \[ \frac{14 \div 2}{8 \div 2} = \frac{7}{4} \]

This still relates back to the initial division of 14 by 8, showing how you end up with \(1.75\) pounds per dessert.

Among the responses provided, none directly reflect this approach, but the closest concepts seem to be trying to simplify or reinterpret the division in incorrect or confusing forms.

Since none of the responses are appropriate as an alternative method to show the division mathematically, I would recommend clarifying that the simplest alternative approach to solving this would still relate back to the original division \(14 \div 8\) or the fraction approach rather than any of the presented erroneous multiplications or divisions in the choices given.

If forced to pick the best among those responses, "4 ÷ 8 = 1 2 pounds" appears to be the most straightforward to correlate with the idea of finding a per-item quantity, but it remains irrelevant as a direct alternative pathway to solve the initial problem stated.