y=7x+8



−7x+y=−8


(1 point)
This system of linear equations has
solution(s).

1 answer

To determine the number of solutions for the given system of linear equations, let's analyze the equations:

  1. \( y = 7x + 8 \)
  2. \( -7x + y = -8 \)

We can rearrange the second equation into the form \( y = mx + b \):

Starting with: \[ -7x + y = -8 \] Adding \( 7x \) to both sides, we get: \[ y = 7x - 8 \]

Now, we can compare the two equations:

  1. \( y = 7x + 8 \)
  2. \( y = 7x - 8 \)

Both equations have the same slope (7), which means they are parallel. Since they have different y-intercepts (8 and -8), they will never intersect. Therefore, there are no solutions.

Thus, the system of linear equations has 0 solutions.