First change the 75 km/h to 20.83 meters per second
(Average Force)* Time = Momentum change
= 1700 kg * 20.83 m/s
Solve or the Average Force, in Newtons
1700(m/s)*20.83(kg)/7.0(s) = ___? N
In pounds, it's about 2300
(Average Force)* Time = Momentum change
= 1700 kg * 20.83 m/s
Solve or the Average Force, in Newtons
1700(m/s)*20.83(kg)/7.0(s) = ___? N
In pounds, it's about 2300
First, let's convert the car's initial velocity from km/h to m/s:
1 km/h = 1000 m/3600 s
So, 75 km/h = (75 * 1000) / 3600 m/s = 20.83 m/s (approximately)
The final velocity of the car when it comes to a stop is 0 m/s.
The change in velocity (Δv) is the final velocity minus the initial velocity:
Δv = final velocity - initial velocity = 0 m/s - 20.83 m/s = -20.83 m/s
The time taken to stop (Δt) is given as 7.0 s.
Using the formula for acceleration (a = Δv / Δt), we can find the acceleration of the car:
a = -20.83 m/s / 7.0 s = -2.98 m/s² (approximately)
Now, we can calculate the average force required to stop the car by multiplying the mass (m) by the acceleration (a):
F = m * a
F = 1700 kg * -2.98 m/s² = -5066 N (approximately)
The average force required to stop the car is approximately 5066 N in the opposite direction of its motion.
acceleration = change in velocity / time taken
First, convert the car's velocity from km/h to m/s:
75 km/h = 75 × (1000 m / 3600 s) = 20.83 m/s (rounded to two decimal places)
Next, calculate the change in velocity. Since the car needs to stop, the final velocity is 0 m/s (car's initial velocity is positive):
change in velocity = final velocity - initial velocity = 0 - 20.83 m/s = -20.83 m/s
Now, use the acceleration formula:
acceleration = change in velocity / time taken
acceleration = (-20.83 m/s) / 7.0 s = -2.98 m/s² (rounded to two decimal places)
The acceleration is negative because the car is decelerating (stopping).
Finally, use Newton's second law to find the average force:
force = mass × acceleration = 1700 kg × (-2.98 m/s²) = -5066 N (rounded to the nearest whole number)
The negative sign indicates that the force is in the opposite direction of the car's initial motion. Therefore, the average force required to stop the car is approximately 5066 N.