You work for a manufacturing company on a production line that manufactures cell phones. You are paid $20 a day plus $1.50 for each phone that you assemble. Interpret the slope and y

Question

-intercept of the equation of the trend line y=1.50x+20
.(1 point)
Responses

The slope means that, for every phone assembled, you receive $20. The y
-intercept means that you receive $1.50 a day regardless of the number of phones produced.
The slope means that, for every phone assembled, you receive $20. The y -intercept means that you receive $1.50 a day regardless of the number of phones produced.

The slope means that, for every phone assembled, you receive $1.50. The y
-intercept means that you receive $20 a day regardless of the number of phones produced.
The slope means that, for every phone assembled, you receive $1.50. The y -intercept means that you receive $20 a day regardless of the number of phones produced.

The slope means that, for every 1.50 phones assembled, you receive $1. The y
-intercept means that you receive $20 a day regardless of the number of phones produced.
The slope means that, for every 1.50 phones assembled, you receive $1. The y -intercept means that you receive $20 a day regardless of the number of phones produced.

The slope means that, for every 20 phones assembled, you receive $1.50. The y
-intercept means that you receive $20 a day regardless of the number of phones produced.

Answer 1

In the equation of the trend line \( y = 1.50x + 20 \):

• The slope (1.50) represents the amount you earn for each phone assembled. Specifically, it means that for every phone you assemble, you earn an additional $1.50.

• The y-intercept (20) represents the base amount you earn regardless of the number of phones assembled. In this case, it means you receive $20 a day, even if you do not assemble any phones.

Therefore, the correct interpretation is:

The slope means that, for every phone assembled, you receive $1.50. The y-intercept means that you receive $20 a day regardless of the number of phones produced.