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Sasha is working on a magic trick with a standard deck of cards. She chooses an ace, puts it back, then chooses a red card. Wha...Question
Sasha is working on a magic trick with a standard deck of cards. She chooses an ace, puts it back, then chooses a red card. What is P(ace|red)
? Round to the nearest tenth.(1 point)
percent
? Round to the nearest tenth.(1 point)
percent
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Answered by
GPT-4o mini
To find \( P(\text{ace} | \text{red}) \), we can use Bayes’ Theorem or consider the problem directly with conditional probability.
1. **Identify the total number of cards**:
A standard deck has 52 cards.
2. **Identify the relevant subsets**:
- There are 4 aces in a deck.
- There are 26 red cards (13 hearts and 13 diamonds).
3. **Calculate \( P(\text{red}) \)**:
The probability of selecting a red card is:
\[
P(\text{red}) = \frac{26}{52} = \frac{1}{2}
\]
4. **Calculate \( P(\text{ace} \cap \text{red}) \)**:
The probability of selecting an ace that is also red (the red aces) is:
\[
P(\text{ace} \cap \text{red}) = \frac{2}{52} = \frac{1}{26}
\]
5. **Now, use the formula for conditional probability**:
\[
P(\text{ace} | \text{red}) = \frac{P(\text{ace} \cap \text{red})}{P(\text{red})}
\]
Substituting the values we have:
\[
P(\text{ace} | \text{red}) = \frac{\frac{1}{26}}{\frac{1}{2}} = \frac{1}{26} \times \frac{2}{1} = \frac{2}{26} = \frac{1}{13}
\]
6. **Convert the probability to a percentage**:
\[
\frac{1}{13} \approx 0.07692
\]
To convert to a percentage, multiply by 100:
\[
0.07692 \times 100 \approx 7.692 \%
\]
7. **Round to the nearest tenth**:
Rounding 7.692% to the nearest tenth gives us:
\[
7.7\%
\]
Therefore, \( P(\text{ace} | \text{red}) \approx 7.7\% \).
1. **Identify the total number of cards**:
A standard deck has 52 cards.
2. **Identify the relevant subsets**:
- There are 4 aces in a deck.
- There are 26 red cards (13 hearts and 13 diamonds).
3. **Calculate \( P(\text{red}) \)**:
The probability of selecting a red card is:
\[
P(\text{red}) = \frac{26}{52} = \frac{1}{2}
\]
4. **Calculate \( P(\text{ace} \cap \text{red}) \)**:
The probability of selecting an ace that is also red (the red aces) is:
\[
P(\text{ace} \cap \text{red}) = \frac{2}{52} = \frac{1}{26}
\]
5. **Now, use the formula for conditional probability**:
\[
P(\text{ace} | \text{red}) = \frac{P(\text{ace} \cap \text{red})}{P(\text{red})}
\]
Substituting the values we have:
\[
P(\text{ace} | \text{red}) = \frac{\frac{1}{26}}{\frac{1}{2}} = \frac{1}{26} \times \frac{2}{1} = \frac{2}{26} = \frac{1}{13}
\]
6. **Convert the probability to a percentage**:
\[
\frac{1}{13} \approx 0.07692
\]
To convert to a percentage, multiply by 100:
\[
0.07692 \times 100 \approx 7.692 \%
\]
7. **Round to the nearest tenth**:
Rounding 7.692% to the nearest tenth gives us:
\[
7.7\%
\]
Therefore, \( P(\text{ace} | \text{red}) \approx 7.7\% \).
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