Asked by kitkat
Angles ABD
and DBC
are supplementary angles (add up to 180°
). If ∡ABD = 3x°
and ∡DBC = 105°
, what is the value of x
?
(1 point)
The equation that solves for x
is
.
Question 2
Solve the equation for x
.(1 point)
x =
(type in the number only)
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and DBC
are supplementary angles (add up to 180°
). If ∡ABD = 3x°
and ∡DBC = 105°
, what is the value of x
?
(1 point)
The equation that solves for x
is
.
Question 2
Solve the equation for x
.(1 point)
x =
(type in the number only)
Skip to navigation
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the value of \( x \), we start with the fact that angles ABD and DBC are supplementary, meaning they add up to \( 180^\circ \).
Given:
- \( \angle ABD = 3x^\circ \)
- \( \angle DBC = 105^\circ \)
We can write the equation:
\[
3x + 105 = 180
\]
Now, we will solve for \( x \).
1. Subtract \( 105 \) from both sides:
\[
3x = 180 - 105
\]
\[
3x = 75
\]
2. Now, divide both sides by \( 3 \):
\[
x = \frac{75}{3}
\]
\[
x = 25
\]
So, the equation that solves for \( x \) is \( 3x + 105 = 180 \), and the value of \( x \) is \( 25 \).
Given:
- \( \angle ABD = 3x^\circ \)
- \( \angle DBC = 105^\circ \)
We can write the equation:
\[
3x + 105 = 180
\]
Now, we will solve for \( x \).
1. Subtract \( 105 \) from both sides:
\[
3x = 180 - 105
\]
\[
3x = 75
\]
2. Now, divide both sides by \( 3 \):
\[
x = \frac{75}{3}
\]
\[
x = 25
\]
So, the equation that solves for \( x \) is \( 3x + 105 = 180 \), and the value of \( x \) is \( 25 \).
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