In the equation \( V = IR \), if the resistance \( R \) is halved (assuming the current \( I \) remains constant), then the voltage \( V \) must also change to maintain the equation.
Since \( R \) is halved, we can express this as:
- New resistance, \( R' = \frac{R}{2} \)
Now, substituting \( R' \) into the equation:
- New voltage, \( V' = I \left(\frac{R}{2}\right) = \frac{IR}{2} \)
Thus, if resistance is halved and current remains constant, then the voltage also changes.
If we consider the relationship given by Ohm's law under constant current, when resistance is halved, the voltage is also halved.
Correct response: The voltage is halved.